LHS: sin x/(1-cos x) +(1-cosx)/sin x# #=(sinx*sinx+(1-cosx)(1-cosx))/(sinx(1-cos x))#->common denominator #=(sin^2 x+1-2cosx+cos^2x)/(sinx(1-cosx)# #=(sin^2 x+cos^2x Explanation We know that ,cos is an even function. ⇒ cos( −θ) = cosθ. ∴ cos(x − π 2) = cos( π 2 −x) = sinx. OR. cos(A −B) = cosAcosB + sinAsinB. cos(x − π 2) = cosxcos( π 2) + sinxsin( π 2) cos(x − π 2) = cosx(0) +sinx(1) = 0 +sinx = sinx. Trigonometry Simplify (1-sin (x))/ (cos (x)) 1 − sin(x) cos (x) 1 - sin ( x) cos ( x) Nothing further can be done with this topic. Please check the expression entered or try another topic. 1−sin(x) cos(x) 1 - sin ( x) cos ( x) Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions Getthe Free Answr app. Click a picture with our app and get instant verified solutions. Click here👆to get an answer to your question ️ int e^x ( 1 - sinx/1 - cosx ) dx =.

Simplifythe numerator. Tap for more steps (1+ sin(x))(1−sin(x)) 1−sin(x) ( 1 + sin ( x)) ( 1 - sin ( x)) 1 - sin ( x) Cancel the common factor of 1−sin(x) 1 - sin ( x). Tap for more steps Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations

Solvefor x sin (x)=4/5. sin(x) = 4 5 sin ( x) = 4 5. Take the inverse sine of both sides of the equation to extract x x from inside the sine. x = arcsin(4 5) x = arcsin ( 4 5) Simplify the right side. Tap for more steps x = 0.92729521 x = 0.92729521. The sine function is positive in the first and second quadrants. Periodicfunctions repeat after a given value. The smallest such value is the period. The basic sine and cosine functions have a period of \(2\pi\). The function \(\sin x\) is odd, so its graph is symmetric about the origin. The function \(\cos x\) is even, so its graph is symmetric about the y-axis. ao9Ms.
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